1.Let A=[a355−1323−4]A = \begin{bmatrix}a&3&5\\5&-1&3\\2&3&-4\end{bmatrix}A=a523−1353−4, B=[b144c1−31d]B = \begin{bmatrix}b&1&4\\4&c&1\\-3&1&d\end{bmatrix}B=b4−31c141d. tr(A)=−4\text{tr}(A)=-4tr(A)=−4 and AB=[−1017−3102528−83]AB = \begin{bmatrix}-1&0&17\\-3&10&25\\28&-8&3\end{bmatrix}AB=−1−328010−817253. Then a+b+c+d=a+b+c+d =a+b+c+d=a.777b.−1-1−1c.333d.111Login to continueOnly logged in users canattempt or see the solution.
