1.Equation of the circle through (3,−2)(3,-2)(3,−2) and (−2,0)(-2,0)(−2,0) with centre on 2x−y−3=02x-y-3=02x−y−3=0 isa.x2+y2+3x+2=0x^2+y^2+3x+2=0x2+y2+3x+2=0b.x2+y2+3x+12y+2=0x^2+y^2+3x+12y+2=0x2+y2+3x+12y+2=0c.x2+y2+2x=0x^2+y^2+2x=0x2+y2+2x=0d.x2+y2=5x^2+y^2=5x2+y2=5Login to continueOnly logged in users canattempt or see the solution.
