1.Let AAA be the set of all functions f:Z→Zf: \mathbb{Z} \to \mathbb{Z}f:Z→Z and RRR be a relation on AAA such that R={(f,g)∣f(0)=g(1) and f(1)=g(0)}R = \{(f,g) \mid f(0) = g(1) \text{ and } f(1) = g(0)\}R={(f,g)∣f(0)=g(1) and f(1)=g(0)}. Then RRR isa.Symmetric and transitive but not reflexiveb.Symmetric but neither reflexive nor transitivec.Reflexive but neither symmetric nor transitived.Transitive but neither reflexive nor symmetricLogin to continueOnly logged in users canattempt or see the solution.
