1.If the greatest value of the term independent of xxx in the expansion of (xsinα+cosαx)10\left(x\sin\alpha + \frac{\cos\alpha}{x}\right)^{10}(xsinα+xcosα)10 is (5!)210!\frac{(5!)^2}{10!}10!(5!)2, then the value of α\alphaα is equal to:a.−1-1−1b.111c.−2-2−2d.222Login to continueOnly logged in users canattempt or see the solution.
