1.If f(x+2y,x−2y)=xyf(x+2y, x-2y) = xyf(x+2y,x−2y)=xy, then f(x,y)f(x, y)f(x,y) is equal toa.xyxyxyb.x2−y24\frac{x^2 - y^2}{4}4x2−y2c.x2−y28\frac{x^2 - y^2}{8}8x2−y2d.x2+y28\frac{x^2 + y^2}{8}8x2+y2Login to continueOnly logged in users canattempt or see the solution.
