1.If limx→0sinxx=A\displaystyle\lim_{x\to0}\frac{\sin x}{x}=Ax→0limxsinx=A and limx→0xsin1x=B\displaystyle\lim_{x\to0}x\sin\frac1x=Bx→0limxsinx1=B, then which is correct?a.A=1,B=0A=1,B=0A=1,B=0b.A=0,B=1A=0,B=1A=0,B=1c.A=0,B=0A=0,B=0A=0,B=0d.A=1,B=1A=1,B=1A=1,B=1Login to continueOnly logged in users canattempt or see the solution.
