1.∫0α/3f(x)f(x)+f((α−3x)/3) dx=\int_0^{\alpha/3} \frac{f(x)}{f(x)+f((\alpha-3x)/3)}\,dx =∫0α/3f(x)+f((α−3x)/3)f(x)dx=a.2α/32\alpha/32α/3b.α/2\alpha/2α/2c.α/3\alpha/3α/3d.α/6\alpha/6α/6Login to continueOnly logged in users canattempt or see the solution.
