1.The binding energy per nucleon of 37Li^{7}_{3}\text{Li}37Li and 24He^{4}_{2}\text{He}24He nuclei are 5.60 MeV5.60\,\text{MeV}5.60MeV and 7.06 MeV7.06\,\text{MeV}7.06MeV, respectively. In the nuclear reaction 7Li+1H→2 4He+Q^{7}\text{Li} + {}^{1}\text{H} \rightarrow 2\,{}^{4}\text{He} + Q7Li+1H→24He+Q, the value of energy QQQ released isa.19.6 MeV19.6\,\text{MeV}19.6MeVb.−2.4 MeV-2.4\,\text{MeV}−2.4MeVc.8.4 MeV8.4\,\text{MeV}8.4MeVd.17.3 MeV17.3\,\text{MeV}17.3MeVLogin to continueOnly logged in users canattempt or see the solution.
