1.If f(x)=sin3xsinx, x≠nπf(x) = \dfrac{\sin 3x}{\sin x},\; x \neq n\pif(x)=sinxsin3x,x=nπ, then the range of values of f(x)f(x)f(x) for real values of xxx isa.[−1,3][-1,3][−1,3]b.(−∞,−1](-\infty,-1](−∞,−1]c.(3,+∞)(3,+\infty)(3,+∞)d.[−1,3)[-1,3)[−1,3)Login to continueOnly logged in users canattempt or see the solution.