1.Let (x+10)50+(x−10)50=a0+a1x+a2x2+⋯+a50x50(x + 10)^{50} + (x - 10)^{50} = a_0 + a_1 x + a_2 x^2 + \dots + a_{50} x^{50}(x+10)50+(x−10)50=a0+a1x+a2x2+⋯+a50x50, for all x∈Rx \in \mathbb{R}x∈R. Then a2a0\dfrac{a_2}{a_0}a0a2 is equal toa.12.512.512.5b.121212c.12.2512.2512.25d.12.7512.7512.75Login to continueOnly logged in users canattempt or see the solution.
