1.The mid-point of a chord of x2+4y2−2x+20y=0x^2+4y^2-2x+20y=0x2+4y2−2x+20y=0 is (2,−4)(2,-4)(2,−4). The equation of the chord isa.x−6y=26x - 6y = 26x−6y=26b.x+6y=26x + 6y = 26x+6y=26c.6x−y=266x - y = 266x−y=26d.6x+y=266x + y = 266x+y=26Login to continueOnly logged in users canattempt or see the solution.