1.Let S={z=x+iy:2z−3i4z+2i is a real number}S = \left\{z = x + iy : \dfrac{2z - 3i}{4z + 2i} \text{ is a real number}\right\}S={z=x+iy:4z+2i2z−3i is a real number}. Then which of the following is NOT correct?a.y+x2+y2≠−14y + x^2 + y^2 \neq -\dfrac{1}{4}y+x2+y2=−41b.(x,y)=(0,−12)(x, y) = \left(0, -\dfrac{1}{2}\right)(x,y)=(0,−21)c.x=0x = 0x=0d.y∈(−∞,−12)∪(−12,∞)y \in \left(-\infty, -\dfrac{1}{2}\right) \cup \left(-\dfrac{1}{2}, \infty\right)y∈(−∞,−21)∪(−21,∞)Login to continueOnly logged in users canattempt or see the solution.
