1.If limx→0x(1+acosx)−bsinxx3=1\displaystyle \lim_{x \to 0} \frac{x(1 + a\cos x) - b\sin x}{x^3} = 1x→0limx3x(1+acosx)−bsinx=1, thena.a=52,b=32a = \frac{5}{2}, b = \frac{3}{2}a=25,b=23b.a=32,b=52a = \frac{3}{2}, b = \frac{5}{2}a=23,b=25c.a=−52,b=−32a = -\frac{5}{2}, b = -\frac{3}{2}a=−25,b=−23d.a=−52,b=32a = -\frac{5}{2}, b = \frac{3}{2}a=−25,b=23Login to continueOnly logged in users canattempt or see the solution.
