1.Let BCBCBC be the diameter of a circle centred at OOO. Point AAA is a variable point on the circumference of the circle. MMM is a point on BCBCBC. If BC=1BC = 1BC=1 unit, then limM→B(Area of sector OAB)2BM\displaystyle \lim_{M \to B} \frac{(\text{Area of sector } OAB)^2}{BM}M→BlimBM(Area of sector OAB)2 is equal toa.111b.222c.444d.161616Login to continueOnly logged in users canattempt or see the solution.