1.Consider the following system of equationsαx+2y+z=1,\alpha x + 2y + z = 1,αx+2y+z=1,2αx+3y+z=1,2\alpha x + 3y + z = 1,2αx+3y+z=1,3x+αy+2z=β,3x + \alpha y + 2z = \beta,3x+αy+2z=β,for some α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R. Then which of the following is NOT correct?a.It has no solution if α=−1\alpha = -1α=−1 and β≠2\beta \neq 2β=2b.It has no solution for α=−1\alpha = -1α=−1 and for all β∈R\beta \in \mathbb{R}β∈Rc.It has no solution for α=3\alpha = 3α=3 and for all β≠2\beta \neq 2β=2d.It has a solution for all α≠−1\alpha \neq -1α=−1 and β=2\beta = 2β=2Login to continueOnly logged in users canattempt or see the solution.