1.The area (in square unit) of the triangle formed by x+y+1=0x + y + 1 = 0x+y+1=0 and the pair of straight lines x2−3xy+2y2=0x^2 - 3xy + 2y^2 = 0x2−3xy+2y2=0 isa.712\frac{7}{12}127b.512\frac{5}{12}125c.112\frac{1}{12}121d.16\frac{1}{6}61Login to continueOnly logged in users canattempt or see the solution.
