1.One mole of ideal gas goes through the process P=2V21+V2P = \dfrac{2V^2}{1+V^2}P=1+V22V2. The change in temperature of the gas when volume changes from V=1 m3V = 1\,\text{m}^3V=1m3 to V=2 m3V = 2\,\text{m}^3V=2m3 isa.115R K\dfrac{11}{5R}\,\text{K}5R11Kb.45R K\dfrac{4}{5R}\,\text{K}5R4Kc.−52R K-\dfrac{5}{2R}\,\text{K}−2R5Kd.2 K2\,\text{K}2KLogin to continueOnly logged in users canattempt or see the solution.
