1.If x2y−x3dydx=y2cosxx^2y - x^3\frac{dy}{dx} = y^2\cos xx2y−x3dxdy=y2cosx, then x3yx^3yx3y is equal toa.sinx\sin xsinxb.2sinx+c2\sin x + c2sinx+cc.−3sinx+c-3\sin x + c−3sinx+cd.3cosx+c3\cos x + c3cosx+cLogin to continueOnly logged in users canattempt or see the solution.
