1.z1=a1−iz_1 = \frac{a}{1-i}z1=1−ia; z2=b2+iz_2 = \frac{b}{2+i}z2=2+ib; z3=a−biz_3 = a - biz3=a−bi for a,b∈Ra, b \in \mathbb{R}a,b∈R. If z1−z2=1z_1 - z_2 = 1z1−z2=1 then the centroid of the triangle formed by the points z1,z2,z3z_1, z_2, z_3z1,z2,z3 in the argand's plane is given bya.19(1+7i)\frac{1}{9}(1 + 7i)91(1+7i)b.13(1+7i)\frac{1}{3}(1 + 7i)31(1+7i)c.13(1−3i)\frac{1}{3}(1 - 3i)31(1−3i)d.19(1−3i)\frac{1}{9}(1 - 3i)91(1−3i)Login to continueOnly logged in users canattempt or see the solution.
