1.The angle between the tangents to the curves y=2x2y = 2x^2y=2x2 and x=2y2x = 2y^2x=2y2 at (1,1)(1, 1)(1,1) isa.tan−1(15/8)\tan^{-1}(15/8)tan−1(15/8)b.tan−1(7/8)\tan^{-1}(7/8)tan−1(7/8)c.tan−1(3/4)\tan^{-1}(3/4)tan−1(3/4)d.tan−1(1/4)\tan^{-1}(1/4)tan−1(1/4)Login to continueOnly logged in users canattempt or see the solution.
