1.f(x)=∫xx+1e−t2dtf(x)=\int_x^{x+1} e^{-t^2}dtf(x)=∫xx+1e−t2dt. Interval where fff is decreasing isa.(−12,∞)(-\frac12,\infty)(−21,∞)b.(−∞,2)(-\infty,2)(−∞,2)c.(−∞,0)(-\infty,0)(−∞,0)d.(−2,2)(-2,2)(−2,2)Login to continueOnly logged in users canattempt or see the solution.