1.If electric flux entering and leaving an enclosed surface is ϕ1\phi_1ϕ1 and ϕ2\phi_2ϕ2, the charge inside isa.(ϕ2−ϕ1)ε0(\phi_2 - \phi_1)\varepsilon_0(ϕ2−ϕ1)ε0b.(ϕ1+ϕ2)/ε0(\phi_1 + \phi_2)/\varepsilon_0(ϕ1+ϕ2)/ε0c.(ϕ2−ϕ1)/ε0(\phi_2 - \phi_1)/\varepsilon_0(ϕ2−ϕ1)/ε0d.(ϕ1+ϕ2)ε0(\phi_1 + \phi_2)\varepsilon_0(ϕ1+ϕ2)ε0Login to continueOnly logged in users canattempt or see the solution.
