1.For the system of equationsx+y+z=6,x + y + z = 6,x+y+z=6,x+2y+αz=10,x + 2y + \alpha z = 10,x+2y+αz=10,x+3y+5z=β,x + 3y + 5z = \beta,x+3y+5z=β,which one of the following is NOT true?a.The system has no solution for α=3,β=24\alpha = 3, \beta = 24α=3,β=24b.The system has a unique solution for α=−3,β=14\alpha = -3, \beta = 14α=−3,β=14c.The system has infinitely many solutions for α=3,β=14\alpha = 3, \beta = 14α=3,β=14d.The system has a unique solution for α=3,β≠14\alpha = 3, \beta \neq 14α=3,β=14Login to continueOnly logged in users canattempt or see the solution.
