1.
The EMF of the cell, Mg∣|Mg2+^{2+} (0.01 M) ∣∣|| Ag+^+ (0.0001 M) ∣| Ag is: (Given EMg2+/Mg∘=−2.37E^\circ_{Mg^{2+}/Mg} = -2.37 V, EAg+/Ag∘=+0.80E^\circ_{Ag^+/Ag} = +0.80 V)