1.The EMF of the cell, Mg∣|∣Mg2+^{2+}2+ (0.01 M) ∣∣||∣∣ Ag+^++ (0.0001 M) ∣|∣ Ag is: (Given EMg2+/Mg∘=−2.37E^\circ_{Mg^{2+}/Mg} = -2.37EMg2+/Mg∘=−2.37 V, EAg+/Ag∘=+0.80E^\circ_{Ag^+/Ag} = +0.80EAg+/Ag∘=+0.80 V)a.2.993 Vb.2.48 Vc.2.993 Vd.3.17 VLogin to continueOnly logged in users canattempt or see the solution.