1.The solution of dxdy+y=ye(n−1)x\frac{dx}{dy} + y = ye^{(n-1)x}dydx+y=ye(n−1)x, (n≠1)(n \neq 1)(n=1)a.1n−1ln(e(n−1)x−1e(n−1)x)=y22+C\frac{1}{n-1} \ln \left( \frac{e^{(n-1)x} - 1}{e^{(n-1)x}} \right) = \frac{y^2}{2} + Cn−11ln(e(n−1)xe(n−1)x−1)=2y2+Cb.e(1−n)x=1+ce(n−1)y22e^{(1-n)x} = 1 + ce^{(n-1)\frac{y^2}{2}}e(1−n)x=1+ce(n−1)2y2c.ln(1+ce(n−1)y22)+nx+1=0\ln \left( 1 + ce^{(n-1)\frac{y^2}{2}} \right) + nx + 1 = 0ln(1+ce(n−1)2y2)+nx+1=0d.e(n−1)x=ce(n−1)+(n−1)y22+1e^{(n-1)x} = ce^{(n-1)+\frac{(n-1)y^2}{2}} + 1e(n−1)x=ce(n−1)+2(n−1)y2+1Login to continueOnly logged in users canattempt or see the solution.
