1.The solution of dydx+xy⋅x2+y2−12(x2+y2)+1=0\frac{dy}{dx} + \frac{x}{y}\cdot\frac{x^2+y^2-1}{2(x^2+y^2)+1} = 0dxdy+yx⋅2(x2+y2)+1x2+y2−1=0 isa.x2+y2+3log(x2+y2)=cx^2 + y^2 + 3\log(x^2 + y^2) = cx2+y2+3log(x2+y2)=cb.x2+3xy−3log(x2+y2+2)=cx^2 + 3xy - 3\log(x^2 + y^2 + 2) = cx2+3xy−3log(x2+y2+2)=cc.x2+2y2−3log(x2+y2+2)=cx^2 + 2y^2 - 3\log(x^2 + y^2 + 2) = cx2+2y2−3log(x2+y2+2)=cd.−x2−2y2−3log(x2+y2)=c-x^2 - 2y^2 - 3\log(x^2 + y^2) = c−x2−2y2−3log(x2+y2)=cLogin to continueOnly logged in users canattempt or see the solution.
