1.Let AAA denote the event that a 6-digit integer formed by 0,1,2,3,4,5,60, 1, 2, 3, 4, 5, 60,1,2,3,4,5,6 without repetitions, be divisible by 333. Then probability of event AAA is equal to:a.956\dfrac{9}{56}569b.49\dfrac{4}{9}94c.37\dfrac{3}{7}73d.1127\dfrac{11}{27}2711Login to continueOnly logged in users canattempt or see the solution.
