1.Let f(x)=∣1+sin2xcos2x4sin2xsin2x1+cos2x4sin2xsin2xcos2x1+4sin2x∣f(x) = \begin{vmatrix} 1+\sin^2 x & \cos^2 x & 4\sin 2x \\ \sin^2 x & 1+\cos^2 x & 4\sin 2x \\ \sin^2 x & \cos^2 x & 1+4\sin 2x \end{vmatrix}f(x)=1+sin2xsin2xsin2xcos2x1+cos2xcos2x4sin2x4sin2x1+4sin2x, then the maximum value of f(x)f(x)f(x) is -a.222b.444c.666d.888Login to continueOnly logged in users canattempt or see the solution.