1.If ∫ex(1+sinx)1+cosxdx=exf(x)+C\int \frac{e^x(1+\sin x)}{1+\cos x}dx = e^x f(x)+C∫1+cosxex(1+sinx)dx=exf(x)+C, then f(x)=f(x)=f(x)=a.\sin(x/2)b.\cos(x/2)c.\tan(x/2)d.\log(x/2)Login to continueOnly logged in users canattempt or see the solution.