1.If 210+29⋅3+28⋅32+…+2⋅39+310=S−2112^{10} + 2^9 \cdot 3 + 2^8 \cdot 3^2 + \ldots + 2 \cdot 3^9 + 3^{10} = S - 2^{11}210+29⋅3+28⋅32+…+2⋅39+310=S−211, then SSS is equal toa.311−2123^{11} - 2^{12}311−212b.3113^{11}311c.311+2103^{11} + 2^{10}311+210d.2⋅3112 \cdot 3^{11}2⋅311Login to continueOnly logged in users canattempt or see the solution.
