1.
Let the distance between the planes 3x+4y+5z+c1=03x+4y+5z+c_1=0 and 3x+4y+5zc2=03x+4y+5z-c_2=0 be 222\sqrt{2}, where c1,c2Wc_1,c_2\in\mathbb{W} (whole numbers). Then the number of possible ordered pairs (c1,c2)(c_1,c_2) is