1.[sin(tan−134)]2+[sin(tan−143)]2=\left[ \sin \left( \tan^{-1} \frac{3}{4} \right) \right]^2 + \left[ \sin \left( \tan^{-1} \frac{4}{3} \right) \right]^2 =[sin(tan−143)]2+[sin(tan−134)]2=a.555b.111c.−1-1−1d.000Login to continueOnly logged in users canattempt or see the solution.
