1.If the sum of the squares of the roots of the equation x2−(sinα−2)x−(1+sinα)=0x^2 - (\sin\alpha - 2)x - (1 + \sin\alpha) = 0x2−(sinα−2)x−(1+sinα)=0 is least, then α\alphaα is equal toa.π/6\pi/6π/6b.π/4\pi/4π/4c.π/3\pi/3π/3d.π/2\pi/2π/2Login to continueOnly logged in users canattempt or see the solution.
