1.Molar conductance of 0.1 M0.1\,\text{M}0.1M acetic acid is 7 Ω−1 cm2 mol−17\,\Omega^{-1}\,\text{cm}^2\,\text{mol}^{-1}7Ω−1cm2mol−1. If the molar conductance of acetic acid at infinite dilution is 380.8 Ω−1 cm2 mol−1380.8\,\Omega^{-1}\,\text{cm}^2\,\text{mol}^{-1}380.8Ω−1cm2mol−1, the value of dissociation constant will bea.226×10−5 mol dm−3226 \times 10^{-5}\,\text{mol dm}^{-3}226×10−5mol dm−3b.1.66×10−3 mol dm−11.66 \times 10^{-3}\,\text{mol dm}^{-1}1.66×10−3mol dm−1c.1.66×10−2 mol dm−31.66 \times 10^{-2}\,\text{mol dm}^{-3}1.66×10−2mol dm−3d.3.442×10−5 mol dm−33.442 \times 10^{-5}\,\text{mol dm}^{-3}3.442×10−5mol dm−3Login to continueOnly logged in users canattempt or see the solution.