1.Let f,g:(1,∞)→Rf,g:(1,\infty)\to\mathbb Rf,g:(1,∞)→R be defined as f(x)=2x+8f(x)=2x+8f(x)=2x+8 and g(x)=x2g(x)=x^2g(x)=x2. If the range of the function f∘g:[2,4]→Rf\circ g:[2,4]\to\mathbb Rf∘g:[2,4]→R is [a,b][a,b][a,b], then a+ba+ba+b is equal to:Login to continueOnly logged in users canattempt or see the solution.
