1.Charge QQQ uniformly distributed over rod AB of length LLL. Potential at point O at distance LLL from end A isa.Q4πε0Lln2\frac{Q}{4\pi\varepsilon_0 L}\ln 24πε0LQln2b.Qln24πε0L\frac{Q\ln 2}{4\pi\varepsilon_0 L}4πε0LQln2c.Q8πε0L\frac{Q}{8\pi\varepsilon_0 L}8πε0LQd.3Q4πε0L\frac{3Q}{4\pi\varepsilon_0 L}4πε0L3QLogin to continueOnly logged in users canattempt or see the solution.
