1.1 mole of heptane (vapour pressure =92 mm of Hg= 92\,\text{mm of Hg}=92mm of Hg) was mixed with 4 moles of octane (vapour pressure =31 mm of Hg= 31\,\text{mm of Hg}=31mm of Hg). The vapour pressure of the resulting ideal solution is:a.46.2 mm of Hg46.2\,\text{mm of Hg}46.2mm of Hgb.40.0 mm of Hg40.0\,\text{mm of Hg}40.0mm of Hgc.43.2 mm of Hg43.2\,\text{mm of Hg}43.2mm of Hgd.38.4 mm of Hg38.4\,\text{mm of Hg}38.4mm of HgLogin to continueOnly logged in users canattempt or see the solution.