1.Let a,b,ca, b, ca,b,c be such that b(a+c)≠0b(a+c) \ne 0b(a+c)=0. If∣aa+1a−1−bb+1b−1cc−1c+1∣+∣a+1b+1c−1a−1b−1c+1(−1)n+2a(−1)n+1b(−1)nc∣=0\begin{vmatrix} a & a+1 & a-1 \\ -b & b+1 & b-1 \\ c & c-1 & c+1 \end{vmatrix} + \begin{vmatrix} a+1 & b+1 & c-1 \\ a-1 & b-1 & c+1 \\ (-1)^{n+2}a & (-1)^{n+1}b & (-1)^n c \end{vmatrix} = 0a−bca+1b+1c−1a−1b−1c+1+a+1a−1(−1)n+2ab+1b−1(−1)n+1bc−1c+1(−1)nc=0then the value of nnn isa.any integerb.zeroc.any even integerd.any odd integerLogin to continueOnly logged in users canattempt or see the solution.
