1.If P=(10121)P = \begin{pmatrix} 1 & 0 \\ \dfrac{1}{2} & 1 \end{pmatrix}P=(12101), then P50P^{50}P50 is:a.(10251)\begin{pmatrix} 1 & 0 \\ 25 & 1 \end{pmatrix}(12501)b.(15001)\begin{pmatrix} 1 & 50 \\ 0 & 1 \end{pmatrix}(10501)c.(12501)\begin{pmatrix} 1 & 25 \\ 0 & 1 \end{pmatrix}(10251)d.(10501)\begin{pmatrix} 1 & 0 \\ 50 & 1 \end{pmatrix}(15001)Login to continueOnly logged in users canattempt or see the solution.
