1.The general solution of 1−x2y2⋅dx=y dx+x dy\sqrt{1 - x^2y^2}\cdot dx = y\,dx + x\,dy1−x2y2⋅dx=ydx+xdy isa.sin(xy)=x+C\sin(xy) = x + Csin(xy)=x+Cb.sin−1(xy)+x=C\sin^{-1}(xy) + x = Csin−1(xy)+x=Cc.sin(x+C)=xy\sin(x + C) = xysin(x+C)=xyd.sin(xy)+x=C\sin(xy) + x = Csin(xy)+x=CLogin to continueOnly logged in users canattempt or see the solution.
