When photon of energy $4.0$ eV strikes the surface of a metal A, the emitted photoelectrons have maximum kinetic energy $T_A$ eV and de-Broglie wavelength $\lambda_A$. The maximum kinetic energy of photoelectron liberated from another metal B by photon of energy $4.50$ eV is $T_B = (T_A - 1.50)$ eV. If the de-Broglie wavelength of these photoelectrons $\lambda_B = 2\lambda_A$, then choose the correct statement(s).