1.% Ionic character of compound AB is ∣Δχ/(χA+χB)∣×100|\Delta\chi/(\chi_A + \chi_B)| \times 100∣Δχ/(χA+χB)∣×100. If χA=1.8\chi_A = 1.8χA=1.8 and χB=2.6\chi_B = 2.6χB=2.6, find % ionic character.a.42.42%b.24.24%c.15.04%d.17.08%Login to continueOnly logged in users canattempt or see the solution.
