1.By applying a force F⃗=(3xy−5z)j^−4k^\vec{F} = (3xy - 5z)\hat{j} - 4\hat{k}F=(3xy−5z)j^−4k^, a particle is moved along the path y=x2y = x^2y=x2 from point (0,0,0)(0, 0, 0)(0,0,0) to the point (2,4,0)(2, 4, 0)(2,4,0). The work done by F⃗\vec{F}F on the particle isa.2805 J\dfrac{280}{5}\,\text{J}5280Jb.1405 J\dfrac{140}{5}\,\text{J}5140Jc.2325 J\dfrac{232}{5}\,\text{J}5232Jd.1925 J\dfrac{192}{5}\,\text{J}5192JLogin to continueOnly logged in users canattempt or see the solution.
