1.Among the two statements(S1):(p∧q)∧(p∧¬q)(S_1): (p \wedge q) \wedge (p \wedge \neg q)(S1):(p∧q)∧(p∧¬q) is a contradiction, and(S2):(p∧q)∨(¬p∧q)∨(p∧¬q)∨(¬p∧¬q)(S_2): (p \wedge q) \vee (\neg p \wedge q) \vee (p \wedge \neg q) \vee (\neg p \wedge \neg q)(S2):(p∧q)∨(¬p∧q)∨(p∧¬q)∨(¬p∧¬q) is a tautology:a.only (S2)(S_2)(S2) is trueb.only (S1)(S_1)(S1) is truec.both are falsed.both are trueLogin to continueOnly logged in users canattempt or see the solution.
