1.The expression ¬(¬p→q)\neg(\neg p \rightarrow q)¬(¬p→q) is logically equivalent toa.p∧¬qp \land \neg qp∧¬qb.¬p∧¬q\neg p \land \neg q¬p∧¬qc.p∧qp \land qp∧qd.¬p∧q\neg p \land q¬p∧qLogin to continueOnly logged in users canattempt or see the solution.
