1.limx→∞(3x−13x+1)4x\displaystyle\lim_{x\to\infty}\left(\frac{3x-1}{3x+1}\right)^{4x}x→∞lim(3x+13x−1)4x equalsa.111b.000c.e−8/3e^{-8/3}e−8/3d.e−4/9e^{-4/9}e−4/9Login to continueOnly logged in users canattempt or see the solution.