1.Two dice are rolled. If both dice have six faces numbered 1,2,3,5,71, 2, 3, 5, 71,2,3,5,7 and 111111, then the probability that the sum of the numbers on the top faces is less than or equal to 888 is:a.49\dfrac{4}{9}94b.1736\dfrac{17}{36}3617c.512\dfrac{5}{12}125d.12\dfrac{1}{2}21Login to continueOnly logged in users canattempt or see the solution.