1.In a Poisson distribution with unit mean, ∑x=0∞∣x−xˉ∣P(X=x)=\sum_{x=0}^{\infty} |x - \bar{x}| P(X = x) =∑x=0∞∣x−xˉ∣P(X=x)=a.eeeb.1e\frac{1}{e}e1c.2e\frac{2}{e}e2d.23e\frac{2}{3e}3e2Login to continueOnly logged in users canattempt or see the solution.