1.a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c}a,b,c are three vectors such that ∣a⃗∣=3|\vec{a}| = 3∣a∣=3, ∣b⃗∣=5|\vec{b}| = 5∣b∣=5, ∣c⃗∣=7|\vec{c}| = 7∣c∣=7. If a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c}a,b,c are perpendicular to the vectors b⃗+c⃗\vec{b} + \vec{c}b+c, c⃗+a⃗\vec{c} + \vec{a}c+a, a⃗+b⃗\vec{a} + \vec{b}a+b respectively, then (a⃗+b⃗+c⃗)2−2=\sqrt{(\vec{a} + \vec{b} + \vec{c})^2 - 2} =(a+b+c)2−2=a.151515b.999c.222222d.252525Login to continueOnly logged in users canattempt or see the solution.
