1.Let A=(4−2αβ)\displaystyle A = \begin{pmatrix} 4 & -2 \\ \alpha & \beta \end{pmatrix}A=(4α−2β). If A2+γA+18I=0A^2 + \gamma A + 18 I = 0A2+γA+18I=0, then det(A)\det(A)det(A) is equal to:a.−18-18−18b.181818c.−50-50−50d.505050Login to continueOnly logged in users canattempt or see the solution.
